To introduce the concept of temperature we need to start from the atomic theory, which considers matter to be composed of atoms.

A useful unit when discussing the mass of atoms is the atomic mass unit [$u$]

$1\mathrm{u}=1.6605\times10^{-27}\mathrm{kg}$

Atoms and molecules are in continual motion, the amount of motion is proportional to the temperature, which we can think of as a measure of energy.

Brownian motion, named after Robert Brown who observed it as random movements of pollen or dust suspended in water was explained by Albert Einstein in 1905 as a product of the thermal motion of molecules or atoms.

We can consider temperature to be a measure of the energy contained in the motion of the microscopic constituents of a material.

To be able to measure temperature we need a scale. The temperature scale in common usage in the United States, Fahrenheit, $\mathrm{^{o}F}$ is based on what may now seem to be fairly arbitrary reference points.

Most of the world uses the Celsius scale, $\mathrm{^{o}C}$, for everyday measurements. This is based on dividing the difference between the freezing point and boiling point of water in to 100 degrees and fixing $0\mathrm{^{o}C}$ as the freezing point.

For thermodynamics an absolute temperature scale, in which 0 is the complete absence of thermal energy, is appropriate. This scale is the Kelvin Scale. In this scale water freezes at $273.15\mathrm{K}$. Note that we do not use a degree symbol for temperatures in Kelvin.

To convert between Farenheit and Celsius you can use the fact that water freezes at $32\mathrm{^{o}F}$ and boils at $212\mathrm{^{o}}F$ to deduce that:

$T(\mathrm{^{o}C})=\frac{5}{9}(T(\mathrm{^{o}F})-32)$

or

$T(\mathrm{^{o}F})=\frac{9}{5}T(\mathrm{^{o}C})+32$

If two objects with different temperatures are brought in to contact with one another thermal energy will flow from one to another until the temperatures are the same, and we then say that the objects are in thermal equilibrium.

The zeroth law of thermodynamics states that:

“If two systems are in thermal equilibrium with a third system, then they are in thermal equilibrium with each other.”

This law may seem obvious but this is only because we already have some expectation from our everyday experience that temperature is a general quantity that we can measure with a thermometer. This law allows to declare this formally, and turns out to be important, in conjunction with the First and Second Laws (we'll talk about these later!), for establishing the true definition of thermal equilibrium.

Most, but not all, materials expand when heated. The change in length of material due to linear thermal expansion is

$\Delta l=\alpha l_{0}\Delta T$

$\alpha$ is the coefficient of linear expansion of the material, measured in $\mathrm{(^{o}C)^{-1}}$

The length of the object after it's temperature has been changed by $\Delta T$ is

$l=l_{0}(1+\alpha\Delta T)$

A material expands in all directions, and if we are interested in the volume changes of a rectangular object, that is isotropic, meaning it expands in the same way in all directions, then

$\Delta V = \beta V_{0}\Delta T$

$V_{0}=l_{0}w_{0}h_{0}$ → $V=l_{0}(1+\alpha\Delta T)w_{0}(1+\alpha\Delta T)h_{0}(1+\alpha\Delta T)$

$\Delta V=V-V_{0}=V_{0}(1+\alpha\Delta T)^{3}-V_{0}=V_{0}[3(\alpha\Delta T)+3(\alpha\Delta T)^{2}+(\alpha\Delta T)^{3}]$

If $\alpha\Delta T << 1$ then $\beta \approx 3\alpha$

Coefficients of thermal expansion can be found here or your textbook.

To solve this problem you need to consider linear thermal expansion. You can use the $l$ given at $20^{o}C$ even though the question asks for $\Delta l$ at $15^{o}C$ ($\Delta l << l$). You will need the linear coefficient of thermal expansion of concrete which can be found here, or in your textbook.

In this problem you need to calculate the volume expansion of the radiator, engine and coolant. The difference between the volume of the coolant and the sum of the volumes of the two containers will be the volume that overflows. You will need the volume coefficients of thermal expansion which you can find either here, or in your textbook.

A Bimetallic Strip combines invar with either copper or brass (ours is brass). The very different coefficients of thermal expansion of the two materials means it bends when heated. Invar is very useful, because of it's low coefficient of thermal expansion. Another material with a very low coefficient of thermal expansion is fused quartz.

Does a hole expand or contract on heating?

Some materials in certain temperature ranges do not expand with temperature. An example is water, which actually decreases in volume as it's temperature is increased from $0\mathrm{^{o}C}$ to $4\mathrm{^{o}C}$. This has an important effect, it explains why the surface of lakes freeze, which helps prevent the flow of heat out of the lake. If the thermal expansion was normal between $0\mathrm{^{o}C}$ and $4\mathrm{^{o}C}$ the circulation effect would continue below $4\mathrm{^{o}C}$ and the whole lake would freeze, starting from the bottom.

What happens when an object wants to expand, but can't because it is fixed?

If an object is trying to expand by a length $\Delta l$ due to thermal expansion, but doesn't because something is holding it in place, that something must be exerting a force.

The force can be found by considering the relationship between stress and material deformation, which we discussed when we introduced elastic moduli.

$\frac{F}{A}=E \frac{\Delta l}{l_{0}}$

And as

$\Delta l=\alpha l_{0}\Delta T$

$\frac{F}{A}=\alpha E \Delta T$

These stresses can be reduced by the inclusion of expansion joints in bridges, roads and pipes.

There are a number of conditions which must be satisfied for a gas to be considered ideal

- There must be a large number of molecules and they should move in random directions with a range of different speeds.
- The spacing between molecules should be much greater than the size of the molecules.
- Molecules are assumed to interact only through collisions.
- The collisions are assumed to be elastic.

At constant temperature, it is found that the product of the pressure and volume of an ideal gas are constant

$PV=\mathrm{constant}$

This is named Boyle's Law, after Robert Boyle who formulated it in 1662.

Joesph Louis Gay-Lussac published Charles' Law in 1802, attributing it to unpublished work of Jacques Charles in the 1780's (Gay-Lussac has his own law..though it's not clear he should!).

Charles' Law states that at constant pressure the volume of a gas is proportional to the temperature.

$V\propto T$

Gay Lussac's Law states that for a fixed volume the pressure is proportional to the temperature

$P\propto T$

The combination of the previous 3 laws implies that

$PV\propto T$

Our previous laws were for systems of constant mass, but we can see that the amount of mass should effect the volume (at a given pressure) or the pressure (at a given volume).

$PV\propto mT$

Measuring the amount of mass in moles will allow us to write the ideal gas law in terms of a universal constant. A mole of gas is a given number of molecules, Avagadro's number, $N_{A}=6.02\times 10^{23}$. If we have a certain mass $m$ of a gas which has a certain molecular mass (measured in atomic mass units, $\mathrm{u}$, which are also the number of grams per mole.), the the number of moles $n$ is given by

$n=\frac{m[\mathrm{g}]}{\textrm{molecular mass}[\mathrm{g/mol}]}$

and

$PV=nRT$ where $R=8.314\mathrm{J/(mol.K)}$

This equation is the ideal gas law

This problem requires the use of the ideal gas law. Watch out for the correct units of temperature and the difference between gauge and absolute pressure.

Another ideal gas law problem. The temperature is different at the bottom and surface of the lake, but you should also pay attention to the pressure as a function of depth.

Another ideal gas law problem. Is the pressure in the ideal gas law absolute or gauge pressure?

The ideal gas law can also be written in terms of the number of molecules $N$

$PV=nRT=\frac{N}{N_{A}}RT=NkT$

where $k=\frac{R}{N_{A}}=\frac{8.314\mathrm{J/(mol.K)}}{6.02\times 10^{23}}=1.38\times 10^{-23}\mathrm{J/K}$ is the Boltzmann Constant.

If $PV=nRT$ the absolute zero temperature occurs when $P=0$. In practice most gases will liquefy before this point, but we can measure the pressure of a fixed volume of gas at a couple of reference points and extrapolate down to zero pressure to get an estimate for absolute zero.

Through laser cooling and molecular trapping techniques it is now possible (but difficult!) for temperatures on the order of a $\mathrm{nK}$ to be achieved. Prof. Dominik Schneble produces ultra-cold ($\mu K$) Bose-Einstein condensates in the basement of this building! Prof. Hal Metcalf was one of the key players in the original development of laser cooling.

We can relate the pressure exerted by an ideal gas on it's container to the change in momentum of a molecule when it strikes the container wall

The average force due to one molecule is then

$F_{molecule}=\frac{\Delta(mv)}{\Delta t}=\frac{2mv_{x}}{2l/v_{x}}=\frac{mv_{x}^{2}}{l}$

The net force on the wall will be the sum of the forces from all $N$ molecules

$F_{net}=\frac{m}{l}\Sigma_{i=1..N} v_{xi}^{2}$

$\frac{\Sigma_{i=1..N} v_{xi}^{2}}{N}=\bar{v_{x}^{2}}$ → $F_{net}=\frac{m}{l}N\bar{v_{x}^{2}}$

$v^{2}=v_{x}^{2}+v_{y}^{2}+v_{z}^{2}$ → $\bar{v^{2}}=\bar{v_{x}^{2}}+\bar{v_{y}^{2}}+\bar{v_{z}^{2}}=\bar{3v_{x}^{2}}$

$F_{net}=\frac{m}{l}N\frac{\bar{v^{2}}}{3}$

$P=\frac{F}{A}=\frac{1}{3}\frac{Nm\bar{v^{2}}}{Al}=\frac{1}{3}\frac{Nm\bar{v^{2}}}{V}$

$PV=\frac{2}{3}N(\frac{1}{2}m\bar{v^{2}})=NkT$

$\bar{KE}=\frac{1}{2}m\bar{v^{2}}=\frac{3}{2}kT$