# Differences

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 phy141:examprep:m1f12 [2012/10/03 15:09]mdawber [Midterm 1 Scores] phy141:examprep:m1f12 [2012/10/03 15:10] (current)mdawber [Midterm 1 Q1 solution (Ave Score: 33.3/35)] Both sides previous revision Previous revision 2012/10/03 15:10 mdawber [Midterm 1 Q1 solution (Ave Score: 33.3/35)] 2012/10/03 15:09 mdawber [Midterm 1 Scores] 2012/09/30 19:59 mdawber [Midterm 1 Information] 2012/09/26 11:29 mdawber [Midterm 1 Information] 2012/09/20 20:35 mdawber [Midterm 1 Information] 2012/09/20 20:34 mdawber 2012/09/20 13:13 mdawber created 2012/10/03 15:10 mdawber [Midterm 1 Q1 solution (Ave Score: 33.3/35)] 2012/10/03 15:09 mdawber [Midterm 1 Scores] 2012/09/30 19:59 mdawber [Midterm 1 Information] 2012/09/26 11:29 mdawber [Midterm 1 Information] 2012/09/20 20:35 mdawber [Midterm 1 Information] 2012/09/20 20:34 mdawber 2012/09/20 13:13 mdawber created Line 86: Line 86: $T=(1+\frac{1}{8}g)=11.025\mathrm{N}$ $T=(1+\frac{1}{8}g)=11.025\mathrm{N}$ - F. How much work is done by gravity on \textbf{the two block system} during the motion in part (C)? + F. How much work is done by gravity on the two block system during the motion in part (C)? $0 \mathrm{J}$ $0 \mathrm{J}$ Line 92: Line 92: OR OR - How much work is done by gravity on \textbf{the two block system} during the motion in part (C)? + How much work is done by gravity on the two block system during the motion in part (C)? $\frac{1}{2}(m_{1}+m_{2})v^{2}=\frac{1}{2}(4)0.6125^{2}=0.75\mathrm{J}$ $\frac{1}{2}(m_{1}+m_{2})v^{2}=\frac{1}{2}(4)0.6125^{2}=0.75\mathrm{J}$